4n^2+17n+15=0

Solution for 4n^2+17n+15=0 equation:

4n^2+17n+15=0

a = 4; b = 17; c = +15;
Δ = b2-4ac
Δ = 172-4·4·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*4}=\frac{-24}{8}
=-3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*4}=\frac{-10}{8}
=-1+1/4
$